India Languages, asked by zohaibsheikh6380, 1 year ago

A force f=5i+3j+2k move a particle r1=2i+7j+4k to r2=5i+2j+8k calculate the work done

Answers

Answered by sibiroopan
2

work =force × displacement.

d=r2 - r1 =5i+2j+8k - 2i+7j+4k =3i-5j+4k

= 5i+3j+2k × 3i-5j+4k = 8 joule.

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