A force F = (5i+3j+2k) N is applied over a particle which displaces it from it's origin to the point r= (2i -j ) m . the work done in the partical in joule is [AIEEE 2004]
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Answer:
work = force × displacement
= 5i+3j+2k× 2i-j
= 10i-3j+2k J
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Answer:
work=force . displacement
work=(5i+3j+2k).(2i-j)=10-3=7joule
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