Physics, asked by MiniDoraemon, 7 months ago

A force F = (5i+3j+2k) N is applied over a particle which displaces it from it's origin to the point r= (2i -j ) m . the work done in the partical in joule is [AIEEE 2004] ​

Answers

Answered by ramandhamija
0

Answer:

work = force × displacement

= 5i+3j+2k× 2i-j

= 10i-3j+2k J

Answered by muskandatwani942
0

Answer:

work=force . displacement

work=(5i+3j+2k).(2i-j)=10-3=7joule

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