Question

A force f = (5i+3j+2k)N is applied over a particle which displaces it from its origin to the point( r=2i-j ) m the work done on the particle is

Answer 1

Here is your answer you just have to divide it direcn wise

Answer 2

Answer:

Work done, W = 7 joules

Explanation:

Given that,

Force applied over a particle, $F=(5i+3j+2k)\ N$

Displacement from its origin, $r=(2i-j)\ N$

We know that the dot product of the force and displacement is equal to the amount of work done. Mathematically, it is given by :

$W=F.r$

$W=(5i+3j+2k).(2i-j)$

We know that, i.i = j.j = k.k = 1

W = 7 joules

So, the work done on the particle is 7 joules. Hence, this is the required solution.