Physics, asked by tharunteja02, 1 year ago

A force F⃗ =(5i^+3j^) N is applied on a particle which displaces it to the point r⃗ =(2i^−j^) m from the origin. The work done on the particle is

Answers

Answered by RAKSH290
2
work= force*displacement
w=f.s
here displacement is (2i^-j^-0-0)=2i^-j^
then,
w=(5i^+3j^).(2i^-j^)
here i.i=1 and j.j=1
w=10-3=7N-m
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