Physics, asked by VAMSU, 11 months ago

A force F =6i +2j-3k acts on a particle
and produces a displacement of
s = 2-3j+xk. If the work done is zero, the
value of x is
1.-2 2.1/2 3.6 4.2​

Answers

Answered by solomoncrazy
4

Explanation:

since

work done =0

W = F . s

F = 6i+2j+3k

s = 2i-3j+xk

F . s =0

(6i+2j+3k)(2i-3j+xk)=0

6(2) + 2(-3) + 3x =0

12 - 6 + 3x =0

6 + 3x = 0

x = -2

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