Question

A force F =(6î -8j)N, acts on a particle and
displaces it over 4 m along the X-axis and 6m
along the Y-axis. The work done during the
total displacement is
Please help me with this question
I will mark you as the branliest

Answer 1

Answer:

Work is the scalar product of force and displacement. It can be expressed as the product of the magnitude of the force and the displacement multiplied by the cosine of the angle between them. The amount of work done is maximum if the force is parallel with the displacement and minimum (zero) if the force is perpendicular with the displacement.

Answer and Explanation:

A.

{eq}\begin{align*} W&=\vec{F}\cdot \Delta \vec{r} \\ &= (8 \hat{i}-3 \hat{j})\ \rm{N} \cdot (4 \hat{i}+ \hat{j}) \ \rm{m}\\ &=[(8)(4)+(-3)(1) ]...

See full answer below.

Answer 2

Explanation:

fu I'm BBC Pg Co by I'm cold endocrine until