Question

A force F=6i-8jN ,acts on a particle and displaces it over 4m along the x-axis and 6m along the y-axis. The work done during the total displacement is​

Answer 1

Explanation:

W=f.s

W =6×4-8×6=-24J

Answer 2

Answer:

- 24 J

Explanation:

Given,

force acting on the particle is, F= 6i-8j N

Since, body displaces through 4 m along x axis and 6 m along y axis.

Hence, the displacement is vector form can be written as 4i + 6j m.

Since, the work done is given by dot product of force acting on the particle and displacement.

So, work done= force. displacement

                       =(6i-8j).( 4i + 6j)

                       = (24- 48) J

                        = -24 J

Hence, the work done during the displacement is - 24 j