A force F=a+bx acts on a particle in the x-directioin, where a and b are constants. Find the work done by this force during a displacement form x=0 to x=d.
Answers
Answered by
1
plz mark brainliest....
Hello Dear.
Here displacement of the particle (S)
= d-0 =d
Now, we have to find the average force.
→Force at x =0
F = a
→Force at x = d
F' = a + bd
∴ Average Force =
Average force = {a + (a + bd) } /2
= a +
Now we know that , work done = F . S
w = { a +
}. d
Hence the work done is [
] d .
Hope it Helps.
Similar questions