Question

A force f acting on an object varies with distance x as shown here. The force is in newton and x is in metre. The work done by the force in moving the object frm x = 0m to x = 6m is

Answer 1

workdone = force × displcmnt
W = f (6 - 0)
W = 6f joule

Answer 2

Answer:

18J is the answer.

Explanation:

W=$\int\limits^0_6 {x} \, dx$=[$\frac{x^{2} }{2}$]upper limit=0 and lower limit=6

W=$\frac{0^{2}-6^{2} }{2}$=$\frac{36}{2}$=18J

Therefore work done by the force in moving the object=18J.

Hope this helps you.