A force f acts between two equal and opposite charges which are placed at
Answers
Answer:
firstly complete your question and then ask please..
Answer:
Given F is the force between the equal and opposite charges.
25 % of the charge is transferred to another.
Thus, + q becomes,
3 over 4 q
Thus, - q becomes,
negative q space plus space 1 fourth q space... left parenthesis space a s space 25 space percent sign space o f space c h a r g e space i s space t r a n s f e r r e d space f r o m space plus q space t o space minus q right parenthesis
= fraction numerator negative 3 over denominator 4 end fraction q
By Coulomb's law,
F apostrophe space equals space fraction numerator k q subscript 1 q subscript 2 over denominator r squared end fraction equals fraction numerator k begin display style 3 over 4 end style q open parentheses begin display style fraction numerator negative 3 over denominator 4 end fraction end style q close parentheses over denominator r squared end fraction
F apostrophe space equals negative k space q squared fraction numerator begin display style bevelled 9 over 16 end style over denominator r squared end fraction space equals space 9 over 16 open parentheses negative fraction numerator k q squared over denominator r squared end fraction close parentheses space equals space 9 over 16 F
Thus, the force between the charges become 9 over 16of the original value.