Question

A force F is applied along a rod of transverse sectional area A . The normal stress to a section PQ inclinef theta to transverse section is

Answer 1

Dear Student:

Force is F

Area is A

The normal stress is given as p cosθ

Where, p is pressure.

And is given as p =F/A

Hence, normal stress=F/A*cosθ

Hence,option 2 is correct.

Hope it helps

Thanks

With Regards

Answer 2

the correct answer is Fcos^2 theta