Physics, asked by gouthamnandha3921, 4 months ago

a force F is applied on a body for a duration of 3 s. the momentum of the body changes from 10 g cm/s to 40bg cm/s the magnitude of the force F is​

Answers

Answered by pranathi47
1

Answer:

T=35dyne/cm −1

=35× 10 −2

10 −5

N/m=35×10 −3

N/m

SE=2×4π×( 100 10 2 )×35×10 −3

=8.8×10 −3 J

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