Question

A force f is applied on a disk at some distance x from the centre. What should be the value of x such that the disk can pure roll even on smooth surface?

Answer 1

will am I right please tell

Answer 2

Answer:

The value of x is 3R/4 for pure rolling of the disc even on a smooth surface.

Explanation:

What is meant by Surface Area?

• The area is the area occupied by a two-dimensional flat surface. It has a square unit of measurement.

• The surface area of a three-dimensional object is the space taken up by its outer surface. The quantity of space enclosing a three-dimensional shape's exterior is its surface area.

• The total amount of space occupied by the surface of a three-dimensional form is measured as surface area (with a three-dimensional shape being a shape with height, width, and depth).

• In other terms, surface area is the sum of the areas of all an object's sides.

Therefore,

$&a_{c m}=\frac{f}{2 m}$

$&a b x f \times x=\left(\frac{m R^2}{2}+m R^2\right) \alpha$

$&\alpha=\frac{f_x}{\frac{3}{2} m R^2}=\frac{2}{3} \frac{f_x}{m R^2}$

$&\Omega=\alpha R$

$&\frac{f}{2 m}=\frac{2}{3} \frac{f x}{m R^2} \cdot R$

$&x=\frac{3 R}{4}$

The complete question is below (Image)

To learn more about Surface Area, refer to:

https://brainly.in/question/43111352

https://brainly.in/question/25926132

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