A force F is applied on a square area of L side if the percentage error in the measurements of L is 2% and the in F is 4% what is the maximum % error i presure
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given=%error of L(square so, L*L)=2%=4%
%error of F=4%
wkt,
p=f/a
applying log on both sides
log p=log f/log a. (log a/b=log^a+b)
=4%+2*2%=8%
answer = 8%
%error of F=4%
wkt,
p=f/a
applying log on both sides
log p=log f/log a. (log a/b=log^a+b)
=4%+2*2%=8%
answer = 8%
Answered by
110
hope it helps you.........
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