Question

A force F = -k(yi + xj) (where k is constant) acts
on a particle moving in the xy plane. Starting from
origin the particle is taken along y-axis to the point
(0, a). The work done by agent applying the force
F on the particle is
(1) K?(x² + y2) (2) Zero
(3) ky
(4) kx​

Answer 1

Answer:

zero

Explanation:

as F=-k(yi+xj)

so,

if the particle moves along the Y-axis then X=0. So, the force long the Y-axis will be zero.

A net variable force will act only along the X-axis as the Y component is not zero and also changing.

as it can be seen that the force is along the X-axis and the displacement is along the Y-axis.

And,

Work done=Force applied X displacement X cos(theta)

And the displacement vector and force vector are along perpendicular axises so, the angle between them will be 90 degrees.

And as the cos90=0.

The work done will also be zero.

plZ MaRK as BrAinLIesT.