A force F of magnitude 20N is applied to a block of mass 2Kg that lies on a rough horizontal surface as shown below in the figure. the coefficient of the kinetic friction between the block and surface is 0.4
a) what is the normal reaction force
b) what is the frictional force between the block and the surface
c) what is the magnitude of the acceleration
( g=10m/s^2 sin53=0.8 cos53=0.6 )
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Answer:
W=Fd
= 20N(2m)
= -40J
Explanation:
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