Question

a force, F, of strength 25 N acts on an object with a mass of 3 kg as it moves a distance of 10 m. If F is perpendicular to the 10m displacement, the work it does is equal to ________.

Answer 1

• 0 J will be the answer as they are perpendicular and work = force × disp. in vector form force =0 as it is perpendicular cos90=0 so work =0

Answer 2

0J as W=F • s = F s cos(theta)

Here theta is angle between force and displacement. Hence theta=90°. So W=0