Physics, asked by tanishajamwal832, 10 hours ago

a force F= xy^2i + yx^2j is acting on a particle which is moving along a parabolic path given by y=x^2. Find the work done by this force in miving the particle from (0,0) to (a,a^2)?

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Answered by fariyalatufa001
0

Answer:

This is the question of  work done

Work done is product of force applied and distance moved.

a force F= xy^2i + yx^2j is acting on a particle which is moving along a parabolic path given by y=x^2.

Work done by this particle

Explanation:

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