Question

a force F1 of 500 newton is required to push a car of mass 100 kg slowly at a constant speed on the level road if a force F 2 of hundred newton is applied the acceleration of car will be​

Answer 1

Answer:

hay mate

Explanation:

F=m×a

putting the value

500=100×a

a=500/100

a=5

F2=100N

F=m×a

100=100×a

a=1

Answer 2

Answer:

The answer is 4 i think!

First-> f1-f2

=500-100

=400

Then

a=?

f=ma

400=100×a

a=400÷100

a=4m/s^2

Is this correct!