Question

A force f⃗ =5i^+6j^+4k^f→=5i^+6j^+4k^ acting on a body, produces a displacement s⃗ =6i^−5k^s→=6i^−5k^ work done by the force is

Answer 1

solution: The work done is given by dot product of Force and Displacement.

i.e, W = F.d = (5I + 6J + 4K).(6I + 5K)  =  5x6 + 4x5 = 30 + 20 = 50 J

Answer 2

● Answer:

Work done, W = 10 joules

● Explanation:

Force acting on the object, F=5i+6j-4kF=5i+6j−4k

Displacement, d=6i+5kd=6i+5k

Work done is given by :

W=F.d

W=(5i+6j-4k).(6i+5k)

Since, i.i = j.j = k.k = 1

W=30-20

W = 10 joules

So, the work done by the force is 10 joules. Hence, this is the required solution.

Hope it helps!✔✔