Question

A force is 24.5 N acts on mass of 5kg for 4 second what velocity does it acquire and how much does it travel in 4 second ?

Answer 1

We know
Force= Mass× Acceleration

f= ma
a= f/m = 24.5/5= 4.9m/sec^2


Now
how do we find value of velocity ??????
v= final velocity, u= initial velocity a=acceleration , t= time

initial velocity=0

v= u +at
v= 0+ 4.9× 4

v= 19.6m/s

and

What is the value of S= distance ????
S= ut+ 1/2×a×t^2
S= 0×4 + 1/2× 4.9××4×4

S= 39.2 meter


so
$velocity = 19.6 \\ distance \: coveredby \: the \: mass = 39.2$
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Answer 2

Answer:

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Explanation:

We know

Force= Mass× Acceleration

f= ma

a= f/m = 24.5/5= 4.9m/sec^2

Now

how do we find value of velocity ??????

v= final velocity, u= initial velocity a=acceleration , t= time

initial velocity=0

v= u +at

v= 0+ 4.9× 4

v= 19.6m/s

and

What is the value of S= distance ????

S= ut+ 1/2×a×t^2

S= 0×4 + 1/2× 4.9××4×4

S= 39.2 meter

so

$$\begin{lgathered}velocity = 19.6 \\ distance \: coveredby \: the \: mass = 39.2\end{lgathered}$$

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