Question

a force is applied for 20 seconds on a non moving body of 5 gms there is no force there after body stopped after 5 seconds moving a distance of 50 cm the value of 4 in Newton is

Answer 1

Hello Dear.

Here is the answer---

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Given Conditions---

Mass of the Body(m) = 5 grams.
                                  = 0.005 kg.

Now,

Distance covered by the Body = 50 cm.
                                                 = 0.5 m.
Time taken by the body to cover this distance = 5 seconds.

⇒ Speed = Distance/Time
                = 0.5/5
                = 0.1 m/s.


Initial Velocity(u) = 0
[Since the body is at rest]
Final Velocity(v) = 0.1 m/s.
Total Time taken = (20 + 5)
                           = 25 seconds.

⇒ $Acceleration = \frac{v - u}{t}$
⇒ $Acceleration = \frac{0.1 - 0}{25}$
⇒ Acceleration = 0.004 m/s²

Now, Using the Newton's Second Law of Motion,

Force = Mass × Acceleration
          = 0.005 × 0.004
          = 0.00002 N.

Thus, the Force acting on the Non-Moving Body is 0.00002 N.


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Hope it helps.

Have a Nice Day.