a force is applied for 20 seconds on a non moving body of 5 gms there is no food there after body stopped after 5 seconds moving a distance of 50 cm the value of force in Newton is
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Hello Dear.
Here is the answer---
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Given---
Mass of the Body(m) = 5 grams.
= 0.005 kg.
Now,
Distance Covered by the body = 50 cm.
= 0.5 m.
Time taken by the body to cover the distance = 5 seconds.
⇒ Speed = Distance/Time
= 0.5/5
= 0.1 m/s.
Initial Velocity(u) = 0
[Since the Body is non-moving and is at rest]
Final Velocity(v) = 0.1 m/s
Total Time = (20 + 5)
= 25 seconds
Thus,
Acceleration = (v - u)/t
= (0.1 - 0)/25
= 1/250 m/s²
Using the Newton's Second Law,
Force = Mass × Acceleration
= 0.005 × 1/250
= 0.00002 N.
→→→→→→→→→→→
Hope it helps.
Have a Marvelous Day.
Here is the answer---
→→→→→→→→→
Given---
Mass of the Body(m) = 5 grams.
= 0.005 kg.
Now,
Distance Covered by the body = 50 cm.
= 0.5 m.
Time taken by the body to cover the distance = 5 seconds.
⇒ Speed = Distance/Time
= 0.5/5
= 0.1 m/s.
Initial Velocity(u) = 0
[Since the Body is non-moving and is at rest]
Final Velocity(v) = 0.1 m/s
Total Time = (20 + 5)
= 25 seconds
Thus,
Acceleration = (v - u)/t
= (0.1 - 0)/25
= 1/250 m/s²
Using the Newton's Second Law,
Force = Mass × Acceleration
= 0.005 × 1/250
= 0.00002 N.
→→→→→→→→→→→
Hope it helps.
Have a Marvelous Day.
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