Physics, asked by pradeepsareen986, 1 year ago

A force is applied for 20s on a non moving body of5g there is no force thereafter. body stopped after 5s moving a distance of 50 cm. the value of force in newton is

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Answered by sachin526
0
Mass of the Body(m) = 5 grams.
                                  = 0.005 kg.

Now,
Distance Covered by the body = 50 cm.
                                                 = 0.5 m.

Time taken by the body to cover the distance = 5 seconds.

⇒ Speed = Distance/Time
               = 0.5/5
               = 0.1 m/s.

Initial Velocity(u) = 0 
 [Since the Body is non-moving and is at rest]
Final Velocity(v) = 0.1 m/s
Total Time = (20 + 5)
                  = 25 seconds

Thus,
 Acceleration = (v - u)/t
                     = (0.1 - 0)/25
                     = 1/250 m/s²

Using the Newton's Second Law,

  Force = Mass × Acceleration
            = 0.005 × 1/250
            = 0.00002 N

Answered by StylishHiba
0
heya
here is ur answer
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