A force is applied for a duration of 10 secs on a body of mass 5 kg which is at rest. As a result the body acquires a velocity of 2m/s. Find the magnitude of force applied?
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HEYA!!
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Given that ,
Time t = 10 seconds
Mass M = 5kg.
Initial velocity u = 0
Final velocity v = 2 m/s.
Force =?
We know that ,
F = ma
So we need to find the acceleration first of all !
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V = U + AT ------[ First equation of motion ]
2 = 0 + 10A
10A = 2
A = 2/10
= 0.2 ms-2.
----------------------------------------------------------------------------------------------------
Force = mass × acceleration
= 5× 0.2
= 1 N
----------------------------------------------------------------------------------------------------
----------
Given that ,
Time t = 10 seconds
Mass M = 5kg.
Initial velocity u = 0
Final velocity v = 2 m/s.
Force =?
We know that ,
F = ma
So we need to find the acceleration first of all !
---------------------------------------------------
V = U + AT ------[ First equation of motion ]
2 = 0 + 10A
10A = 2
A = 2/10
= 0.2 ms-2.
----------------------------------------------------------------------------------------------------
Force = mass × acceleration
= 5× 0.2
= 1 N
----------------------------------------------------------------------------------------------------
DevilDoll12:
yeah !! got it
yeah there is another one...wanna try?
what's that now ??
anyway this was the simple method
a vehicle of mass 120kg is moving with a velocity of 90km/h. what force should be applied to stop it in 5 secs?
have u posted it as a question?
naah
I cant solve in comment sec
lol my bad!
pls post it
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