Question

A force is applied on a body of 0.9 kg that is at rest. The force is applied for a duration of 5s and as a result the body covers a distance of 250m. Find the magnitude of the force.

Answer 1

Distance = 250m
Time = 5 seconds
Initial velocity (u) = 0m/sec ( since, body is at rest)
So,
$s = ut + \frac{1}{2} a {t}^{2}$
So,
280 = 0 + 1/2* a * 25
Or, 250 = 25/2a
Or,a =250*2/25 = 20m/sec²

Now,
From NEWTON'S second law of motion
F= MA
Or,
F = 0.9 * 20 = 18N

Hope this will be helping you

WARM REGARDS
Sahil khirwal