A force is applied on a body of mass 0.9 kg that is at rest. the force applied for duration of 5s and as a result the body covers a distance of 250 m. find the magnitude of the force
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a=F/m. (1)(as F=ma)
s=ut+(1/2)at^2.
here , u=0 , a=F/0.9 , s=250m
substituting these values in the above equation ,
250=(1/2)F/0.9 × 5^2
after solving we get F=18newton
s=ut+(1/2)at^2.
here , u=0 , a=F/0.9 , s=250m
substituting these values in the above equation ,
250=(1/2)F/0.9 × 5^2
after solving we get F=18newton
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