Question

a force is applied on a body of mass 0.9kg that is at rest the force is applied for duration of 5s and body covers distance of 250m find the magnitude of force with explanation

Answer 1

★Initial velocity=0

★★constant acceleration should be here because force is applicable for whole 5 second and it is constant.

$\red{since\: accleration\:is\: constant\:so\:we\: can\:use\:equation\:of\:motion}$

★Distance covered=250m
★time=5sec

By equation of motion-
$s = ut + \frac{1}{2} a {t}^{2} \\250 = 0 + \frac{1}{2} a ({5}^{2} ) \\ \\ a = \frac{500}{25} \\ a = 20$
◆◆acceleration=20m/s^2◆◆

Force=mass×acceleration
=0.9×20
18N

$\boxed{\red{Force=18N}}$