a force is applied on a body of mass 20 kg moving with a velocity of 40 metre per second the body attains a velocity of 15 metre per second in 2 seconds calculate the work done by the body
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mass of the body is equal to 20 kg let us take the mass of the body as m.
then initial velocity of body is 40 m per second let us take the initial velocity of the body as u.
final velocity of the body is 15 M per second let us take the final velocity as v
time taken is 2 second let us take it as t.
now work done is equal to change in kinetic energy of the body
therefore initial kinetic energy of the body will be 1/2 mu^2 = 1/2×20×40×40=16000 joules
final kinetic energy of the body will be half mv^2 = 1/2×20×15×15 =2250 hence work done will be final kinetic energy minus initial kinetic energy.
therefore the answer will be 13750 joules. hope the answers help you
then initial velocity of body is 40 m per second let us take the initial velocity of the body as u.
final velocity of the body is 15 M per second let us take the final velocity as v
time taken is 2 second let us take it as t.
now work done is equal to change in kinetic energy of the body
therefore initial kinetic energy of the body will be 1/2 mu^2 = 1/2×20×40×40=16000 joules
final kinetic energy of the body will be half mv^2 = 1/2×20×15×15 =2250 hence work done will be final kinetic energy minus initial kinetic energy.
therefore the answer will be 13750 joules. hope the answers help you
SamirsonuKumar807656:
sorry I forget to send the full answer
I'm sending here
Dindi final kinetic energy of the body will be 1/2 mv^2 =1/2×20×15×15=2250 joules
then work done will be equal to final kinetic energy - initial kinetic energy = 16000 minus 2250 therefore answer is 13750 joules
hope the answer helps you
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