Question

a force is applied on a body of mass 20 kilogram moving with a velocity of 40 metre per second the body tensor velocity of 50 M per second into second calculate the work done by the body​

Answer 1

Let,

M1= initial momentum

M2= final momentum

M1= 20×40=800 kgm/s

M2=20×50=1000 kgm/s

F=(m2-m1)/2=100N

Let,

A= acceleration=100/20=5m/s^²

now

S= displacement=ut+1/2at^²

=40×2+0.5×5×4=90m

W=F×S=9000J

I hope this answers...is correct...