Physics, asked by aayuthor, 1 month ago

A force is applied on a body of mass 25 kg moving with a velocity of 3 m/s. the body attains a velocity of 50 m/s in 2 seconds. Calculate the work done by the body and Power developed.​

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Answered by HarshOzWiz
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Answered by harisreeps
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Answer:

A force is acting on a body of mass 25 kg moving with a velocity of 3 m/s. the body attains a velocity of 50 m/s in 2 seconds, the work done by the body is 31137.5Nm and Power developed is 15568.7Nm/s

Explanation:

  • The work done (W) is the product of the force (F) applied and displacement(d) of the body due to the applied force, that is

        W=F.d

  • From Newton's second law F=ma
  • The acceleration is the change in velocity with time a=(v-u)/t
  • From the equation of motion, the distance moved by an accelerated body is      s=ut+\frac{1}{2}at^{2}
  • Power of a body is the work done per unit done P=W/t

From the question, we have

mass of the body m=25kg

the initial velocity of the body u=3m/s

the final velocity v=50m/s

time taken for this change t=2s

the acceleration of the body

a=\frac{50-3}{2} =47/2=23.5m/s^{2}

now force on the body F=25*23.5=587.5N

the distance traveled s=3*2+\frac{1}{2} *23.5*2^{2} =53m

therefore required work done W=587.5*53=31137.5Nm

power of the body P=31137.5/2=15568.7Nm/s

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