a force is applied on a car of mass 1500 kg so that its speed increases from 54 km/h to 72 km/h.find the work done by force on the car
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Answered by
13
GIVEN,
u = 54 km/h = 54*5/18 = 15 m/s
v = 72 km/h = 72*5/18 = 20 m/s
m = 1500 kg
kinetic energy = 1/2*m(v^2 - u^2)
1/2*1500(20*20 - 15*15)
750(400 - 225)
750*175
131250 J
u = 54 km/h = 54*5/18 = 15 m/s
v = 72 km/h = 72*5/18 = 20 m/s
m = 1500 kg
kinetic energy = 1/2*m(v^2 - u^2)
1/2*1500(20*20 - 15*15)
750(400 - 225)
750*175
131250 J
Answered by
8
Given:
Mass, m= 1500 kg
u = 54 km/h
= 54 × 5/18= 15 m/s
v= 72 km/h
= 72 × 5/18 = 20 m/s
W= K.E = ?
K.E = 1/2 m (v^2 - u^2)
= 1/2 × 1500 × (20×20- 15×15)
=750 × (400-225)
= 750 × 175
= 131250
K.E = 131250 J
Mass, m= 1500 kg
u = 54 km/h
= 54 × 5/18= 15 m/s
v= 72 km/h
= 72 × 5/18 = 20 m/s
W= K.E = ?
K.E = 1/2 m (v^2 - u^2)
= 1/2 × 1500 × (20×20- 15×15)
=750 × (400-225)
= 750 × 175
= 131250
K.E = 131250 J
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