a force is applied prependicularly on a door 400 cm wide which required a torque of 1200 Nm to open it . what will be the minimum force required
Answers
Answered by
5
Answer:
300 newton
Step-by-step explanation:
torque=force*distance
force= 1200/4 ( distance should be in metres as torque is in Nm)
so force=300 Newton
Answered by
6
Answer:
The answer is 300N
Step-by-step explanation:
Torque is 1200
Distance is 400 cm which has to be calculated in metre
It will be 4 m
We know,
Torque = Force * Perpendicular distance
1200 = Force * 4
therefore force will be 300 Newton
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