A force is applied to a mass of 16 kg for 3 seconds. As the force is removed the mass moves 81 meters in 3 seconds. What was the value of the force applied?
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The value of the force applied is 144 N.
Explanation:
Given mass, m = 16 kg.
The mass moves a distance, d = 81m in time t = 3s
The velocity,
v = 81 m/3 s = 27 m/s.
Since mass moves in 3 s is 81 m when the force removed.
Therefore, the mass moves with uniform velocity (no acceleration) for next 3 s.
a = (27 m/s - 0)/(3s)
a = 9 m/s ^ 2
Now to calculate the force use Newton law of motion,
F= ma
F = 16 kg * 9 m/s ^ 2
F = 144N
Thus, the value of the force applied ( in first 3 s) is 144 N.
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