Question

A force is applied to an 8.0 kg object initially at rest.

The magnitude of the net force varies with time as

shown. What is the speed of the object at t = 15 s.

Answer 1

Answer:

15F/8=V

Explanation:

F=ma

F=8(v-u)/t

F=8(v-0)/15

F=8v/15

15F/8=v

Answer 2

Answer:

15F/8=V

Explanation:

F=8(V-U)t

F=8(V-0)15

F=8v/15

15F/8=V

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