A force is given by F=at+bt² where t' is the time. The dimensions of a and b are.
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SOLUTION-;
⇒ Since F=at+bt 2 −−−(1)
∴ Dimension of at and bt 2
must be equal to force only.
Hence [F]=[M 1 L 1 T −2 ]−−−(2)
F from (1) and (2)
⇒ [at]=a[T]=[F]
∴ a[T]=[M 1 L 1 T −2 ]
∴ [a]=[M 1 L 1 T −3 ]
and per bt 2 =b[T 2 ]=[M L 1 T −2 ] ∴ [b]=[M 1 L 1 T −4
]
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