A force is given by F = at + bt2 , where t is time . The dimentions 0 of a and b are
Answers
Answered by
0
⇒ Since F=at+bt
2
−−−(1)
∴ Dimension of at and bt
2
must be equal to force only.
Hence [F]=[M
1
L
1
T
−2
]−−−(2)
F from (1) and (2)
⇒ [at]=a[T]=[F]
∴ a[T]=[M
1
L
1
T
−2
]
∴ [a]=[M
1
L
1
T
−3
]
and per bt
2
=b[T
2
]=[M
1
L
1
T
−2
]
Answered by
0
Explanation:
Since F=at+bt2 −−−(1)
∴ Dimension of at and bt 2 must be equal to force only.
Hence [F]=[M1 L1 T-2 ]−−−(2)
F from (1) and (2)
⇒ [at]=a[T]=[F]
∴ a[T]=[M1 L1 T−2 ]
∴ [a]=[M1 L1 T-3]
and per bt 2
=b[T2 ]=[M1 L1T-2]
∴ [b]=[M1 L1 T-4]
Hope it helps
Similar questions