A force is inclined at 30 degree to the x-axis if the component of force in x-axis is 50n. find the magnitude of force
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hey mate here is ur Ans
Force along X ais =Fcos(30)
=> Fcos(30)i=50N
=>Fsin(30)j
=> |F|=√[{Fcos(30)}^2+{Fsin(30)^2]
=> F=[100]√10/3
Force along X ais =Fcos(30)
=> Fcos(30)i=50N
=>Fsin(30)j
=> |F|=√[{Fcos(30)}^2+{Fsin(30)^2]
=> F=[100]√10/3
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