a force is inclined at 50 to the horizontal direction be 50n find the magnitude of force and its vertical component?
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Let the force be F
it is inclined at 50 degree with horizontal.
So F cos50 = 50N
⇒ F = 50/cos50 N
⇒ F = 77.78 N
vertical component, F sin50 = 77.78×sin50 = 59.58
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Answered by
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A force inclined at 50 ° to horizontal , if it's component in this direction is 50 N , find magnitude of force and its vertical components.
Here ,
But
Therefore ,
Also ,
Hope it helps dear....
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