Question

a force is inclined at 60 to the horizontal I it's rectangular component in the horizontal direction in 50 n then magnitude of the force in the vertical direction is options a 25 n b 75 n c 100 n d 87n​

Answer 1

Answer:

Explanation:

horizontal component of force = fcos60 = 50N ---------------------(1)

vertical component of force = fsin60

usinf equation 1 , we get f = 100N  

now , put the value of f in vertical component

vertical component = 100 X 31/2/2 = 100 X 0.866 = 86.6 N

Answer 2

Answer: F cos60 = 50N

so F/2 = 50 or F = 100N

hence vertical component is

Fsin60 = (100 × sqrt (3) )/2 =50×sqrt3 N

Explanation: