Question

A force is inclined at 60' to the horizontal . If the horizontal component of force is 40 kg wt, calculate the vertical component.

Answer 1

vertical component,F = F sin 60 degree = 80 *0.866= 69.28 kg
                              2

Answer 2

let the force be F
given that horizontal component is =40
                                  F cos60=40
                                         F/2=40
                                         F=80
now vertical component ,Fsin60=80*√3/2
                                              =40√3 ans.....