Question

A force is inclined at 60° to the horizontal. if its rectangular component in the horizontal directon is 50 n, the magnitude of force in the vertical direction is?

Answer 1

vertical force Is fsintheta find f and put the values

Answer 2

$x = 50 \\ \\ \alpha = 60° \\ \\ \tan( \alpha ) = \frac{x}{y} \\ \\ y = 50 \tan(60°) \\ \\ y = 50 \times \sqrt{3} = 87N$