a force (mv^2 /r) is acting on a body of mass M with a velocity V in a circular path of radius R , what is the work done by the force in moving the body over half the circumference of the circle?
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The force acting on the object is the centripetal force (MV^2/R). We know, if the object is moving on a circular path, the direction of its displacement changes continuously, and is always perpendicular to the direction of force (force always acts towards the centre of the circle). Now, since the force and displacement are always perpendicular, angle between them is 90°.
Work done = F•S = Fs cos theta = Fs × cos 90
Work done = Fs × 0 = 0 Joules
I hope you've understood :)
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