Question

A force of 0.01 N is exerted on the charge of 1.2×10-5 C at a certain point.the electric field at the point is

Answer 1

Answer:

E=F/q

Explanation:

apply above formula you will get the answer

Answer 2

Answer:

8.3*10^2 NC^-1

Explanation:

GIVEN:

          Force [F]=0.01 N

          Charge [Q]=1.2*10^-5 C

Electric field is defined as the force experienced per unit charge.[E]

therefore,

               E=F/Q

               E=0.01/1.2*10^-5

               if you solve this you will get

               E=8.3*10^2 NC^-1.

HOPE IT IS USEFUL.