Question

A force of 0.032 N is required to move a charge of 42uc

in
an
electric field
between two
25cm apart. What
Potential difference enist between the two
points ?

​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

potential difference is equal to 190.75

Step-by-step explanation:

Charge(q) =  42uc

Force = 0.032 N

Distance = 0.25m

V =?

$E = Force\div q$ = 0.032/(42×10⁻⁶)

E = 761.9 V

also,  $E=$ $dv\div dr$ ⇒ dv=E(dr)

= 761.9 × 0.25

= 190.75

Thus potential difference is equal to 190.75