Question

A force of 0.04 newton acts on a body of mass 1 kg the acceleration of the body is

Answer 1

Answer:

0.04 m / sec²

Explanation:

Given :

Force F = 0.04 N

Mass m = 1 kg

We are asked to find acceleration.

We know :

F =  m a

Putting given values we get :

0.04 = 1 × a

a = 0.04 m / sec²

Therefore , acceleration of the body is 0.04 m / sec².

Answer 2

Answer:

• Acceleration (a) Produced is 0.04 m/s².

Given:

1. Applied Force (F) = 0.04 N.
2. Mass of the Body (M) = 1 Kg.

Explanation:

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Newton's Second Law:

The rate of change of momentum is directly proportional to the Applied external Force on a body.

Expression:

• F ∝ dP/dt
• F = Ma

Units:

• S.I Unit = Newton (N)
• C.G.S Unit = Dynes (d)

Dimensional Formula:

• M L T⁻²

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Now, From the Formula,

⇒ F = Ma

Where,

• F denotes applied force.
• M denotes mass.
• a denotes acceleration.

Substituting the values,

⇒ F = m × a

⇒ 0.04 N = 1 Kg × a

⇒ 0.04 = 1 × a

⇒ a = 0.04 / 1

⇒ a = 0.04

⇒ a = 0.04 m/s².

∴ Acceleration (a) Produced is 0.04 m/s².

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