Question

A force of 0.4N acts on a mass of 4kg at rest.Calculate it's velocity and momentum at the end of 10s.

Answer 1

According to second law of motion

F = ∆P /t

∆P = pf - pi. ( pi= 0 rest)

∆P = F×t = 4Kgm/s

∆p =mv = 4

v= 4/4 = 1m/s .

or.

a = F/M.

Answer 2

The velocity and the momentum of the object is 1 m/s and 4 kg-m/s respectively.

Explanation:

Given that,

Force, F = 0.4 N

Mass of the object, m = 4 kg

Time, t = 10 s

If a is the acceleration of the object. Force s given by :

F = ma

$a=\dfrac{F}{m}$

$a=\dfrac{0.4\ N}{4\ kg}$

$a=0.1\ m/s^2$

Acceleration is given by :

$a=\dfrac{(v-u)}{t}$

u = 0 (initially)

$a=\dfrac{v}{t}$

$v=\dfrac{at}{1}$

$v=0.1\times 10=1\ m/s$

The momentum of the object is given by :

p = mv

$p=4\times 1=4\ kg-m/s$

So, the velocity and the momentum of the object is 1 m/s and 4 kg-m/s respectively.

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Kinematics

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