Question

A force of 0.6gf acts on golf ball of 200g for 12s. If initially the ball is at rest then calculate the final velocity and distance covered. take g = 1000 cm/s2

Answer 1

F=600dyne =600g cm ^-2

m=200g

Acceleration =a=F/m=600gcm^-2/200g

a=3cm^-2

t=12s

Initial velocity = u=0

1) final velocity = v=?

v=u+at

v=0+3×12

v= 36cms^-1

Distance covered = s=?

v^2-u^2=2as

36^2 -0^2=2×3s

s=36×36/6

s= 216cm

Hopeit helps u mate

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Answer 2

State four effects, which a force can bring about, giving two examples in each case. ... (b) Force at distance : A force which acts upon a body, without the aid of a ... If initially the ball is at rest, calculate the final velocity and distance covered. ( Take g = 1000 cm s 2 ) Ans. F = 0.6 gf = = 600 dynes; u = 0; m = 200 g; t = 12 s;