Question

A force of 0.6n acting on a particle increases its velocity from 5m/s to 6 m/s in 2s. the maa of the particle ig

Answer 1

F=ma
F=m×dv/dt
0.6=m×(6-5)/2
0.6=m×1/2
m=0.6×2
m=1.2kg is answer obtained

Answer 2

$\huge{\mathcal{Hi\: there!}}$

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$\underline{\bold{Given :}}$

Initial velocity ( u ) = 5 m/s.

Final velocity ( v ) = 6 m/s.

Time taken ( t ) = 2 secs.

Force ( f ) = 0.6 N.

$\underline{\bold{Solution :}}$

We will find the acceleration of the body, using first equation of motion ;

v = u + at

⇒ 6 = 5 + a × 2

⇒ 6 - 5 = 2a

⇒ 2a = 1

⇒ a = 1 / 2

⇒ a = 0.5 m/s².

Now,

Force = mass × acceleration

⇒ Mass = $\mathsf {\frac{force}{acceleration} }$

⇒ Mass = $\mathsf {\frac{0.6 N}{0.5 m / s{} ^{2} } }$

⇒ Mass = 1. 2 kg.

Hence, the mass of the particle is 1.2 kg.
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Thanks for the question !

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