Question

A force of 1.0 N acts on a body at rest and covers 100 cm in 4 seconds moving along a straight line. The mass of the body is


(a) 2 kg

(b) 4 kg

(c) 6 kg

(d) 8 kg

​

Answer 1

Given:-

• Force acting on Body = 1N

• Initial Velocity of Body = 0m/s

• Distance Covered = 100cm = 1m

• Time taken = 4s.

To Find:-

• The mass of the Body.

Formulae used:-

• S = ut + ½ × a × t²

• F = ma

Where,

• S = Distance
• u = Initial Velocity
• t = Time
• a = Acceleration
• F = Force
• m = Mass

Now,

→ S = ut + ½ × a × t²

→ 1 = (0)(4) + ½ × a × (4)²

→ 1 = 0 + ½ × a × 16

→ 1 = 8a

→ 1/8 = a

→ a = 0.125m/s²

Now Again,

→ F = ma

→ 1 = m × 0.125

→ 1 = 0.125m

→ m = 1/0.125

→ m = 8kg

Hence, The mass of the Body is 8kg.

Answer 2

please mark as brainliest answer

Given:-

Force acting on Body = 1N

Initial Velocity of Body = 0m/s

Distance Covered = 100cm = 1m

Time taken = 4s.

To Find:-

The mass of the Body.

Formulae used:-

S = ut + ½ × a × t²

F = ma

Where,

S = Distance

u = Initial Velocity

t = Time

a = Acceleration

F = Force

m = Mass

Now,

→ S = ut + ½ × a × t²

→ 1 = (0)(4) + ½ × a × (4)²

→ 1 = 0 + ½ × a × 16

→ 1 = 8a

→ 1/8 = a

→ a = 0.125m/s²

Now Again,

→ F = ma

→ 1 = m × 0.125

→ 1 = 0.125m

→ m = 1/0.125

→ m = 8kg

Hence, The mass of the Body is 8kg.